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6x^2+1x-29=0
We add all the numbers together, and all the variables
6x^2+x-29=0
a = 6; b = 1; c = -29;
Δ = b2-4ac
Δ = 12-4·6·(-29)
Δ = 697
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{697}}{2*6}=\frac{-1-\sqrt{697}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{697}}{2*6}=\frac{-1+\sqrt{697}}{12} $
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